Coding Test/LeetCode
[LeetCode] 1464. Maximum Product of Two Elements in an Array c++
owls
2023. 2. 21. 15:47
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문제
Given the array of integers nums, you will choose two different indices i and j of that array. Return the maximum value of (nums[i]-1)*(nums[j]-1).
Input: nums = [3,4,5,2]
Output: 12
Explanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12.
문제 해결
class Solution {
public:
int maxProduct(vector<int>& nums) {
int first = 0, second = 0;
for( const int& number: nums){
if( number > first ){
second = first;
first = number;
}else if( number > second ){
second = number;
}
}
return ( first - 1 ) * ( second - 1 );
}
};
다른 풀이
class Solution {
public:
int maxProduct(vector<int>& nums) {
priority_queue<int> pq(begin(nums), end(nums));
int result = (pq.top() - 1);
pq.pop();
result *= (pq.top() - 1);
pq.pop();
return result;
}
};
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