[HackerRank] Compare the Triplets c++

• Problem

Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.

The rating for Alice's challenge is the triplet a = (a[0], a[1], a[2]), and the rating for Bob's challenge is the triplet b = (b[0], b[1], b[2]).

The task is to find their comparison points by comparing a[0] with b[0], a[1] with b[1], and a[2] with b[2].

• If a[i] > b[i], then Alice is awarded 1 point.
• If a[i] < b[i], then Bob is awarded 1 point.
• If a[i] = b[i], then neither person receives a point.

Comparison points is the total points a person earned.

Given a and b, determine their respective comparison points.

• Example

a = [1, 2, 3]
b = [3, 2, 1]

 For elements *0*, Bob is awarded a point because a[0] .

The return array is [1, 1] with Alice's score first and Bob's second.

• Constraints

1 ≤ a[i] ≤ 100

1 ≤ b[i] ≤ 100

• Sample Input

5 6 7
3 6 10

• Sample Output

1 1

 

• Solutions

vector<int> compareTriplets(vector<int> a, vector<int> b) {
    vector<int> res(2, 0);
    for(int i = 0; i < a.size(); i++){
        if(a[i] > b[i]) res[0] += 1;
        else if(a[i] < b[i]) res[1] += 1;
    }
    return res;
}

hackerrank Compare the Triplets c++