[HackerRank] Grading Students c++

• Problem

HackerLand University has the following grading policy:

- Every student receives a  grade in the inclusive range from 0 to 100 .

- Any grade less than 40 is a failing grade.

Sam is a professor at the university and likes to round each student's grade according to these rules:

- If the difference between the  and the next multiple of 5 is less than 3, round  grade up to the next multiple of 5.

- If the value of grade is less than 38 grade, no rounding occurs as the result will still be a failing grade.

• Example

grade = 84 round to  85 (85 - 84 is less than 3)

grade = 29  do not round (result is less than 40)

grade = 57  do not round (60 - 57 is 3 or higher)

Given the initial value of  grade for each of Sam's n students, write code to automate the rounding process.

• Constraints

1<= n <= 60

0<= grades[i] <= 100

• Sample Input

4
73
67
38
33

• Sample Output

75
67
40
33

• Explanation

ID	Original Grade	FInal Grade
1	73	75
2	67	67
3	38	40
4	33	33

1. Student 1 received a 73, and the next multiple of 5 from 73 is 75. Since 75-73<3, the student's grade is rounded to .
2. Student 2 received a 67, and the next multiple of 5 from 67 is 70. Since 70-67 = 3, the grade will not be modified and the student's final grade is 67.
3. Student 3 received a 38, and the next multiple of 5 from 38 is 40. Since 40-38<3, the student's grade will be rounded to 40.
4. Student 4 received a grade below 33, so the grade will not be modified and the student's final grade is 33.

• Solutions

vector<int> gradingStudents(vector<int> grades) {
    vector<int> res;
    for(auto &it : grades){
        int n = 0, tmp = 0;
        n = it % 5;
        tmp = 5 - n;
        if(tmp >= 3)    res.push_back(it);
        else if(it+tmp >= 40){
            res.push_back(it+tmp);
        } 
        else{
            res.push_back(it);
        }
    }
    return res;
}